LR = KOS

[cry;]

So I saw a lot of people fighting abt lrs being kos or not so lemme explain  a bit. lr can only happen when there are 4 or less ts left, lr means last request which, by name is their "last request" supposedly before death. Whether the t wins or loses the lr they are kos unless it was interrupted, via a rebelling prisoner or a accidental cheat in lr. if the ct in lr is killed by a rebelling t the t in the lr is not kos and should send a new lr. The ct has to choice to pardon the t and let them re-lr if they win but its not required as the t is kos already.

[delirium]

Thank you for regurgitating the rules. I don't think anyone who has access to the forums and plays jailbreak doesn't already know this or where the rules thread is.

[20 scrolls]

Adding on, if the CT slays, the T is NOT kos as they didn't win the LR (LR is complete once either the T or CT kills the opposing opponent)

[Ero]

Also even thought the T didint " kill " the ct winning rock paper scissors is kos .

[cry;]

1 minute ago, Ero said:

Also even thought the T didint " kill " the ct winning rock paper scissors is kos .

yes because they won the lr

[ArcticWolf]

To anyone that is confused on the rules or what jailbreak is you can just read this thread.

 

[20 scrolls]

An LR is considered complete when the T kills the CT, either party wins rock paper scissors, or when the CT kills the T. If a CT slays during an LR, the LR is NOT complete therefor the T is not kos.

If a T cheats LR they are kos, but CTs are not allowed to cheat LR UNLESS dealing with a rebelling T.

Rule definition:
"LRs are considered to be complete when the winning party kills the losing party or wins Rock Paper Scissors. A Prisoner may request to do another LR after the previous one is completed, but Guards are not required to honor this request and the Prisoner may be killed."